#### Тема: Help on my math homework (quadratic formula)?

A quadratic function can be graphed using a table of values. The graph creates a parabola. The parabola contains specific points, the vertex, and up to two zeros or x-intercepts. The zeros are the points where the parabola crosses the x-axis.

Given the following function:
h(x) = 1/2x 2 - x +2

• Predict whether the parabola will open up or down.
• Find the x coordinate of the vertex using the vertex formula.
• Create a table of values and graph the parabola.
• Identify the zeros of function.

x = [5±sqrt(73)]/4

It may help to start by graphing the function on your calculator (assuming you are allowed to use a calculator) by entering the function as it appears into y1. Set the window values to center around the origin. Example: both x and y values range from -25 to 25. A graph of the function shows that it does not cross the x-axis; there are no real zeros and no x-intercept. You can show this mathematically by expanding the function. f(x)= -2 (x-4)(x-4) - 18 f(x)= -2 (x^2-4x-4x+16) - 18 f(x)= -2x^2+16x-32-18 f(x)=-2x^2+16x-50 Because the leading coefficient of the quadratic (-2) is negative, the function is concave down. It has a vertical translation that shifted it down 50 units as well, meaning that the vertex (peak) of the function occurs at x=-50, far below the x-axis. You can see these values in your graph of the function. To solve for y-intercepts, simply set the function equal to zero. f(x)=-2(x-4)-18=0 Solve this equality for x; the value of x indicates the point on the graph where the function crosses the y-axis. Unfortunately, as far as I am aware, there are no y-intercepts for your function either. This is entirely possible, but also may just be because I misread your f(x) equation. I did the math by hand & also checked it with a special program in my calculator; both indicated that there are no real solutions.

Varsity Tutors connects learners with experts. Instructors are independent contractors who tailor their services to each client, using their own style, methods and materials.

Varsity Tutors connects learners with experts. Instructors are independent contractors who tailor their services to each client, using their own style, methods and materials.

Online Tutorials
(over 3,000 lessons + 10,000 quiz questions)

A quadratic function can be graphed using a table of values. The graph creates a parabola. The parabola contains specific points, the vertex, and up to two zeros or x-intercepts. The zeros are the points where the parabola crosses the x-axis.

If the coefficient of the squared term is positive, the parabola opens up. The vertex of this parabola is called the minimum point.

I assume that the equation is 3x^2 + 12x + 7 = 0 The Quadratic Formula: for ax^2 + bx + c = 0: x = (-b + or - SQR(b^2 - 4ac))/2a so x = (-12 + or - SQR(144 - 4(3)(7)))/2(3) x = (-12 + or - SQR(144 - 84))/6 x = (-12 + or - SQR(60))/6 simplify as desired, you will get two answers called roots. The second part of your question makes no sense, there is no y in the equation.

Home » Functions » Vertex Formula Using the Vertex Formula Quadratic Functions - Lesson 2. Before we begin this lesson on using the vertex formula, let's briefly.

Varsity Tutors connects learners with experts. Instructors are independent contractors who tailor their services to each client, using their own style, methods and materials.