When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt
A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.
How far away from Deb s house will the faster train pass the other train?
Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.
I know the answer, but I don''''''''''''''''''''''''''''''''t understand the reasoning or how to get it.
This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:
Let us take a look at some simple examples of distance, time and speed problems.
Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?
Time = Distance / speed = 20/4 = 5 hours.
Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.
A rate is a ratio that compares two different kinds of numbers, such as miles per hour or dollars per pound. A unit rate compares a quantity to its unit of measure. A unit price is a rate comparing the price of an item to its unit of measure.
The rate miles per hour gives distance traveled per unit of time. Problems using this type of rate can be solved using a proportion , or a formula .
It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.
A bus traveling at an average rate of 50 kilometers per hour made the trip to town in 6 hours. If it had traveled at 45 kilometers per hour, how many more minutes would it have taken to make the trip?