Тема: Dog Problems Solved — Behaviour Problems, Puppy Issues.

It’s not a war. When we normally start an argument we see each other as two opponents that have an issue to “debate”. Therefore we get angry, maybe yell at each other, blame each other and we forget that we actually have a relationship and that we love each other.

So the idea here is: when you’re having an argument to remember that you are both on the same side, it’s not a war, it’s your relationship and the real enemy is the conflict itself not your partner. Thus you want to work on solving the conflict together rather than blaming each other.

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Let us take a look at some simple examples of distance, time and speed problems.

Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?

Time = Distance / speed = 20/4 = 5 hours.

Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don't understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Order essay here time and distance solved problems

It’s not a war. When we normally start an argument we see each other as two opponents that have an issue to “debate”. Therefore we get angry, maybe yell at each other, blame each other and we forget that we actually have a relationship and that we love each other.

So the idea here is: when you’re having an argument to remember that you are both on the same side, it’s not a war, it’s your relationship and the real enemy is the conflict itself not your partner. Thus you want to work on solving the conflict together rather than blaming each other.

For understanding comprehension you should have a good reading skills. You should read your personal favourite books to a larger extent and try to speed up your reading skills.Look for new words in the dictionary everyday. We cant directly resolve questions without reading text. It is big mistake that anybody does in comprehension. Keeping in view the above facts it is essentially important to manage time as it is the key factor for our success. Every question should be given the same time. If you consider the above facts you will surely do well in English. And the most important above all never hesitate and take things difficult. Everything would go right on your way. Best of Luck.

Area is simply the space inside of your shape. Perimeter is simply the length of the sides of your shape, added up. The easiest area to find is of a square, simply square one side and you got its area. To find the perimeter of a square, just take on side, and add it to the the other three sides. For example, you have a square and one of its sides has a length of 4cm. Its area would be 16cm(squared), and the perimeter would be 4+4+4+4 = 16cm. For rectangles, its just Length x Width to find the area. Perimeter is just the same. Adding up all the sides. Sorry, I have no idea what grade level you are in of geometry. Therefore, I m explaining at a 5th grade level.

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Loneliness and missing our partner like crazy it’s what makes long distance relationships challenging. But there are ways in which we can make time feel like.

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

10

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''''''''''''''''''''''''''''''''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Let us take a look at some simple examples of distance, time and speed problems.

Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?

Time = Distance / speed = 20/4 = 5 hours.

Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

A rate is a ratio that compares two different kinds of numbers, such as miles per hour or dollars per pound. A unit rate compares a quantity to its unit of measure. A unit price is a rate comparing the price of an item to its unit of measure.

The rate miles per hour gives distance traveled per unit of time. Problems using this type of rate can be solved using a proportion , or a formula .

It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.

A bus traveling at an average rate of 50 kilometers per hour made the trip to town in 6 hours. If it had traveled at 45 kilometers per hour, how many more minutes would it have taken to make the trip?

11

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''''''''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Let us take a look at some simple examples of distance, time and speed problems.

Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?

Time = Distance / speed = 20/4 = 5 hours.

Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''''''''''''''''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Let us take a look at some simple examples of distance, time and speed problems.

Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?

Time = Distance / speed = 20/4 = 5 hours.

Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

A rate is a ratio that compares two different kinds of numbers, such as miles per hour or dollars per pound. A unit rate compares a quantity to its unit of measure. A unit price is a rate comparing the price of an item to its unit of measure.

The rate miles per hour gives distance traveled per unit of time. Problems using this type of rate can be solved using a proportion , or a formula .

13

When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
d = rt

A train leaves Deb s house and travels at 50 miles per hour. Two hours later, another train leaves from Deb s house on the track beside or parallel to the first train but it travels at 100 miles per hour.

How far away from Deb s house will the faster train pass the other train?

Plane A leaves los Angeles for York @ 500 mph, at the same time
plane b leaves from York for Los Angeles @650mph. Assume the distance from
los Angeles to York is 3000 miles, find how long it will take them to meet.

(2.6 hours)

I know the answer, but I don''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''t understand the reasoning or how to get it.

This was his second attempt at sending us this problem. The first time, he left out the numbers and just wanted us to help with the concept, which was okay; but, more importantly, he stated the problem mistakenly that first time. What he wrote then was:

Let us take a look at some simple examples of distance, time and speed problems.

Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?

Time = Distance / speed = 20/4 = 5 hours.

Example 2. A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

A rate is a ratio that compares two different kinds of numbers, such as miles per hour or dollars per pound. A unit rate compares a quantity to its unit of measure. A unit price is a rate comparing the price of an item to its unit of measure.

The rate miles per hour gives distance traveled per unit of time. Problems using this type of rate can be solved using a proportion , or a formula .

It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.

A bus traveling at an average rate of 50 kilometers per hour made the trip to town in 6 hours. If it had traveled at 45 kilometers per hour, how many more minutes would it have taken to make the trip?